A stone is thrown upward from the top of a 59.4m high cliff with an upward velocity component of 19.6m/s how long is the stone in the air?

A. 4.00 s
B. 5.00 s
C. 6.00 s
D. 7.00 s

Applying newtons formula,

S= ut + (1/2)at^2

Let downwards direction be (-) be

, so

-59.4 = 19.5t – (1/2) 10t^2

By Sloving this you will get ,t= 6 sec

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