I. x2 + 11x + 30 = 0,
II. y2 + 15y + 56 = 0 to solve both the equations to find the values of x and y?

Quadratic Equations 06/10/2020

A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y

Explanation:

I. x2 + 6x + 5x + 30 = 0
=>(x + 6)(x + 5) = 0 => x = -6, -5
II. y2 + 8y + 7y + 56 = 0
=>(y + 8)(y + 7) = 0 => y = -8, -7
=> x > y

Related Mcqs:

    Find the roots of the quadratic equation: x2 + 2x – 15 = 0?
    A. -5, 3 B. 3, 5 C. -3, 5 D. -3, -5...
    Find the roots of the quadratic equation: 2×2 + 3x – 9 = 0?
    A. 3, -3/2 B. 3/2, -3 C. -3/2, -3 D. 3/2, 3...
    The sum of the square of the three consecutive even natural numbers is 1460. Find the numbers?
    A. 18, 20, 22 B. 20, 22, 24 C. 22, 24, 26 D. 24, 26, 28...
    (i). a2 + 11a + 30 = 0,
    (ii). b2 + 6b + 5 = 0 to solve both the equations to find the values of a and b?
    A. If a < b B. If a ≤ b C. If the relationship between a and b cannot be established D. If a > b...
    I. a2 + 8a + 16 = 0,
    II. b2 – 4b + 3 = 0 to solve both the equations to find the values of a and b?
    A. If a < b B. If a ≤ b C. If the relationship between a and b cannot be established D. If a > b...

Leave a Reply

Your email address will not be published. Required fields are marked *