In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?

A. 5/21
B. 5/14
C. 9/14
D. 16/21

Explanation:

Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)

As remaining person can be any one among three couples left.
Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅
= (10 * 6)/252 = 5/21