Search
.Management Sciences
A. 1 hr
B. 2 hrs
C. 6 hrs
D. 8 hrs
Explanation:
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
1/x + 1/(x + 6) = 1/4
x2 – 2x – 24 = 0
(x – 6)(x + 4) = 0 => x = 6.
Related Mcqs:
- Two taps can separately fill a cistern 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
- A. 7 min B. 13 min C. 23 min D. 9 min...
- Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?
- A. 6 min B. 12 min C. 19 min D. 10 min...
- Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in___________?
- A. 17 hours B. 12 hours C. 16 hours D. 24 hours...
- A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is?
- A. 6 hrs B. 10 hrs C. 15 hrs D. 30 hrs...
- Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
- A. 10 min 20 sec B. 11 min 45 sec C. 12 min 30 sec D. 14 min 40 sec...
Recent Comments