A path of uniform width turns the inside of a rectangular field 38m long and 32m wide. IF the path occupies 600 m² than the width of the path is_______?

A. 3m
B. 5m
C. 8.75m
D. 10m

Explanation:

Area of the field = (38 x 32)m2

Let the width of the path be x metres
Area with out path = (38-2x)(32-2x)m²
= 1216+4x² -140x

Area of the path = 1216 –(1216 +4×2 -140x)
= 140x -4x² 140x -4x² = 600
=> 4×2-140x +600 =0
=> x² -35x +150 =0
=> (x-30)(x-5)=0
=> X =5 m